If the diameter of the base of a cylinder is $7 c m$ and volume $577.5 c m^{3}$ Find the height of the cylinder

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Solution

d=7 cm r= 7/2 cm
$v = 577.5 c m^{3}$
h=?
$v = π r^{2} h$
$577.5 = \frac{22}{7} \times (\frac{7}{2})^{2} \times h$
$= 877.5 = \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times b$
$= 577.5 = \frac{77}{2} h$
$= \frac{577.5 \times 2}{7} = 165$ $∴ h = 165 c m$

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If the diameter of the base of a cylinder is 7 cm and volume 577.5 cm3 Find the height of the cylinder

d=7 cm r= 7/2 cmv=577.5cm3h=?v=πr2h577.5=227×(72)2×h=877.5=227×72×72×b=577.5=772h=577.5×27=165 ∴h=165cm

If the diameter of the base of a cylinder is $7 c m$ and volume $577.5 c m^{3}$ Find the height of the cylinder

d=7 cm r= 7/2 cm
$v = 577.5 c m^{3}$
h=?
$v = π r^{2} h$
$577.5 = \frac{22}{7} \times (\frac{7}{2})^{2} \times h$
$= 877.5 = \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times b$
$= 577.5 = \frac{77}{2} h$
$= \frac{577.5 \times 2}{7} = 165$ $∴ h = 165 c m$