If the difference between median and mean of a moderately symmetric distribution is 12 then find the difference between mode and mean

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 36
For any given data, $M o d e = 3 M e d i a n - 2 M e a n$
So, $3 M e d i a n - 2 M e a n = M o d e$
$=> 2 M e d i a n + M e d i a n - 2 M e a n = M o d e$
$=> 2 (M e d i a n - M e a n) = M o d e - M e d i a n$
Given, $M e d i a n - M e a n = 12$
$=> M o d e - M e d i a n = 2 (M e d i a n - M e a n) = 2 \times 12 = 24$
$m e d i a n - m e a n = 12$
$m o d e - m e d i a n = 24$
simply add both the above equation
$m o d e - m e a n = 36$

Suggest Corrections

Similar questions

12

50

37.5

M o d e = 3 M e d i a n - 2 M e a n

36

Join BYJU'S Learning Program