You visited us 1 times! Enjoying our articles? Unlock Full Access!

Characteristics of Bohr's Atomic Model

If the differ...

Question

If the difference between $(n + 1)^{t h}$ Bohr radius and $n^{t h}$ Bohr radius is equal to the $(n - 1)^{t h}$ Bohr radius then find the value of $n$

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4$
Radius of $n^{t h} o r b i t$ is $r_{n} = n^{2} r_{0}$ where $r_{0}$ is radius of ground state.
Given that $(n + 1)^{2} r_{0} - n^{2} r_{0} = (n - 1)^{2} r_{0}$
Solving above equation will result in $n = 4$

Suggest Corrections

Similar questions

Q. The difference between

(n + 2)^{t h}

Bohr radius and

n^{t h}

Bohr radius is equal to the

(n - 2)^{t h}

Bohr radius. The value of

n

is:

Q. Difference between

n t h

and

(n + 1) t h

Bohr's radius of hydrogen atom is equal to

(n - 1) t h

Bohr's radius. The value of

n

Difference between $n^{t h}$ and $(n + 1)^{t h}$ Bohr's radius of `H' atom is equal to it's $(n - 1)^{t h}$ Bohr's radius. The value of n is approximately ___.

Q. Given

r_{n + 1} - r_{n - 1} = 2 r_{n}

, where

r_{n}, r_{n - 1}, r_{n + 1}

are Bohr radius for hydrogen atom in

n^{t h}, (n - 1)^{t h}, (n + 1)^{t h}

shells respectively. The value of

n

is:

Q. The difference

n^{t h}

and

(n + 1)^{t h}

Bohr's radius of

H

-atoms is equal to

(n - 1)^{t h}

Bohr's radius. Hence the value of

^{'} n^{'}

is :

Join BYJU'S Learning Program

If the difference between (n+1)th Bohr radius and nth Bohr radius is equal to the (n−1)th Bohr radius then find the value of n

The correct option is A 4Radius of nthorbit is rn=n2r0 where r0 is radius of ground state.Given that (n+1)2r0−n2r0=(n−1)2r0Solving above equation will result in n=4

If the difference between $(n + 1)^{t h}$ Bohr radius and $n^{t h}$ Bohr radius is equal to the $(n - 1)^{t h}$ Bohr radius then find the value of $n$

The correct option is A $4$
Radius of $n^{t h} o r b i t$ is $r_{n} = n^{2} r_{0}$ where $r_{0}$ is radius of ground state.
Given that $(n + 1)^{2} r_{0} - n^{2} r_{0} = (n - 1)^{2} r_{0}$
Solving above equation will result in $n = 4$