If the difference between pressure inside and outside of a soap bubble is 6 mm of water above atmospheric pressure and its radius is 8 mm. What is the surface tension in dynes per cm :
The excess pressure inside a bubble is given by the expression,
P = 4Tr
Since, the value of this expression is given as 6mm of water
Pexcess=103×9.8×0.006 = 58.8 N
This should be equal to the excess pressure developed.
58.8=4T0.008
Solving, T = 0.116 N/m or 116 dyne/cm