Question

If the dimension of a physical quantity is given by $\left[M^a{L}^b{T}^c\right]$ then the physical quantity will be

• A. acceleration, if a = 1, b =-1, c =-2
• B. velocity, if a = 1, b =0, c =-1
• C. pressure, if a = 1, b =-1, c =-2
• D. force, if a = 0, b =-1, c =-2

Answer 1

Answer: (C)

pressure, if a = 1, b =-1, c =-2

Pressure, $P=\frac{Force}{Area}=\frac{Mass\times Acceleration}{Area}$

$\left[P\right]=\frac{M{L}^1{T}^{-2}}{L^2}=\left[M^1{L}^{-1}{T}^{-2}\right]=\left[M^a{L}^b{T}^c\right]$

$a=1,b=-1,c=-2$