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Question

If the dimension of a physical quantity is given by [MaLbTc] then the physical quantity will be

A
acceleration, if a = 1, b =-1, c =-2
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B
velocity, if a = 1, b =0, c =-1
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C
pressure, if a = 1, b =-1, c =-2
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D
force, if a = 0, b =-1, c =-2
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Solution

The correct option is B pressure, if a = 1, b =-1, c =-2
Pressure, P=ForceArea=Mass×AccelerationArea

[P]=ML1T2L2=[M1L1T2]=[MaLbTc]

a=1,b=1,c=2

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