If the dimensions of a box is 6 m - 4 m - 5 m- then its volume is-A- 120 m 3B- 158 m 3C- 132 m 3D- 128 m 3

The correct option is A 120 m^3 Volume of the box = Length × Breadth × Height =6 m × 4 m × 5 m =120 m ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard V

Mathematics

Volume of Cube and Cuboid.

If the dimens...

Question

If the dimensions of a box is $6 m \times 4 m \times 5 m$ , then its volume is:

$120 m^{3}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$158 m^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$132 m^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$128 m^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$120 m^{3}$

$V o l u m e o f t h e b o x = L e n g t h \times B r e a d t h \times H e i g h t$
$= 6 m \times 4 m \times 5 m$
$= 120 m^{3}$
Therefore, volume of the box will be $120 m^{3}$ .

Suggest Corrections

Similar questions

If the dimensions of a box is $6 m \times 4 m \times 5 m$ , then its volume is:

Q. A cuboid-shaped box has dimensions 4 m×3 m×2 m.Match the no. of boxes of given volume that can fit in the box.

Q. What are the forces imparted by atmosphere on the walls of a room of dimension

6 m \times 5 m \times 4 m

? (

1

Atm. =

10^{5} N / m^{2}

What is the length of a box if its volume= $60 m^{3}$ , breadth = $4 m$ and height = $3 m$ ?

A metallic sheet is of rectangular shape with dimensions 48 m $\times$ 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m $^{3}$ ) is:

Join BYJU'S Learning Program

If the dimensions of a box is 6 m×4 m×5 m, then its volume is:

The correct option is A 120 m3 Volume of the box =Length×Breadth×Height =6 m×4 m×5 m =120 m3 Therefore, volume of the box will be 120 m3.

If the dimensions of a box is $6 m \times 4 m \times 5 m$ , then its volume is:

The correct option is A
$120 m^{3}$

$V o l u m e o f t h e b o x = L e n g t h \times B r e a d t h \times H e i g h t$
$= 6 m \times 4 m \times 5 m$
$= 120 m^{3}$
Therefore, volume of the box will be $120 m^{3}$ .