Question

If the dimensions of a physical quantity are given by $M^a{L}^b{T}^c$, then the physical quantity will be:

• A. Force if a = 0, b = –1, c = -2
• B. Pressure if a = 1, b = –1, c = -2
• C. Velocity if a = 1, b = 0, c = -1
• D. Acceleration if a = 1, b = 1, c = -2

Answer 1

The correct option is B Pressure if a = 1, b = –1, c = -2

Dimensional formula
Force = $ML{T}^{-2}$
Pressure = $M{L}^{-1}{T}^{-2}$
Velocity =$L{T}^{-1}$
Acceleration = $L{T}^{-2}$
On comparing with $M^a{L}^b{T}^c$
We get pressure with a = 1, b = -1, c = -2