Question

If the dimensions of a physical quantity are given by $M^a{L}^b{T}^c$, then the physical quantity will be

• A. velocity if $a=1,b=0,c=-1$
• B. acceleration if $a=1,b=1,c=-2$
• C. force if $a=0,b=-1,c=-2$
• D. pressure if $a=1,b=-1,c=-2$

Answer 1

The correct option is D pressure if $a=1,b=-1,c=-2$

Velocity $=m/s=L{T}^{-1}$
Acceleration $=m/s^2=L{T}^{-2}$
Force $=kg.m/s^2=ML{T}^{-2}$
Pressure $=kg/m.s^2=M{L}^{-1}{T}^{-2}$