Question

If the dipole moment of $HBr$ is $2.60\times {10}^{-30}Cm$ and the interatomic spacing is $1.41\mathring{A}$ , then the percent iconic character of $HBr$ is:

• A. 16.23%
• B. 13.21%
• C. 11.50%
• D. 15.81%

Answer 1

The correct option is C 11.50%

Theoretical value of dipole moment of a 100% ionic character $=e\times d$

$=(1.60\times {10}^{-19}C)(1.41\times {10}^{-10}m)$

$=2.26\times {10}^{-30}Cm$

$\therefore$ % ionic character $=\frac{Observedvalue}{Theoreticalvalue}\times 100$

$=\frac{2.60\times {10}^{-30}}{2.26\times {10}^{-29}}\times 100=11.5$

Hence, option C is correct.