If the directioncosines of a line are 1c-1c-1c then c-

The correct option is C ±√(3) If direction cosines are ( 1c, #160;1c, #160;1c) ⇒ (1c)^2+ (1c)^2 + (1c)^2 = 1 ⇒ c^2 = 3 ⇒ c=±√(3) ...

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Factorization Method Form to Remove Indeterminate Form

If the direct...

Question

If the direction cosines of a line are $(\frac{1}{c}, \frac{1}{c}, \frac{1}{c})$ then $c =$ ______

3

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1 / \sqrt{3}

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\pm \sqrt{3}

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\pm \frac{1}{\sqrt{3}}

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(\frac{1}{c}, \frac{1}{c}, \frac{1}{c})

c = \pm \sqrt{3}

y = m_{1} x + c_{1}, y = m_{2} + c_{2} a n d y = m_{3} x + c_{3}

m_{1} (c_{2} - c_{3}) + m_{2} (c_{3} - c_{1}) + m_{3} (c_{1} - c_{2}) = 0

If the three lines $y = m_{1} x + c_{1}, y = m_{2} x + c_{2}$ and $y = m_{3} x + c_{3}$ are concurrent then show that,

$m_{1} (c_{2} - c_{3}) + m_{2} (c_{3} - c_{1}) + m_{3} (c_{1} - c_{2}) = 0$

(\frac{a^{3}}{a - 1}, \frac{a^{2} - 3}{a - 1}), (\frac{b^{3}}{b - 1}, \frac{b^{2} - 3}{b - 1})

(\frac{c^{3}}{c - 1}, \frac{c^{2} - 3}{c - 1})

a, b, c

1,

l x + m y + n = 0

a_{1} b_{1} c_{1}, a_{2} b_{2} c_{2}

a_{3} b_{3} c_{3}

Δ = ∣ ∣ ∣ ∣ \begin{matrix} c_{1} & a_{1} & b_{1} c_{2} & a_{2} & b_{2} c_{3} & a_{3} & b_{3} \end{matrix} ∣ ∣ ∣ ∣

Δ

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