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Question

If the direction of cosines of a vector are 352,452 and 12 respectively, then the vector is:

A
3^i+4^j+^k
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B
3^i+4^j+5^k
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C
32^i+42^j+^k
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D
3^i+4^j+5^k
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Solution

The correct option is A 3^i+4^j+^k
Given, the direction cosines,

(a|a|,b|b|,c|c|)=(352,452,12)

Then the direction ratios, (a,b,c)=(3,4,1)

We know equation of a vector, v=a^i+b^j+c^k

Then the vector with given direction ratios will be v=3^i+4^j+^k

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