Question

If the discriminant of $3x^2-14x+k=0$ is $100$, then $k=$

• A. $8$
• B. $32$
• C. $16$
• D. $24$

Answer 1

The correct option is A $8$

Given that, the discriminant of $3x^2-14x+k=0$ is $100$.

To find out: The value of $k$.

We know that, the discriminant of a quadratic equation of the form $a{x}^2+bx+c=0$ is given by,

$D=b^2-4ac$

Here, $a=3,b=-14,c=k$

So, $D=(-14{)}^2-4(3)k$

$\Rightarrow (-14{)}^2-4(3)k=100$

$\Rightarrow 196-12k=100$

$\Rightarrow 12k=96$

$\Rightarrow k=8$

Hence, the value of $k$ is $8$.