If the displacement of a body is directly proportional to square of time, the object moves with
a) uniform velocity
b) uniform acceleration
c) increasing acceleration
d) decreasing acceleration
Please tell the correct option and explain

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Solution

Displacement is proportional to square of time

s is displacement and t is time then,

s∝t^2

s=kt^2
velocity(v) =ds/dt =2kt

acceleration = dv/dt =2k= constant

So, the motion of body is constant acceleration.

option b is right

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If the displacement of an object is proportional to the square of time, then the object is moving with :

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Q. Question 4
If the displacement of an object is proportional to square of time, then the object moves with
(a) uniform velocity
(b) uniform acceleration
(c) increasing acceleration
(d) decreasing acceleration

Q. If a body starts from rest and moves with uniform acceleration, then the displacement of the body is directly proportional to the cube of the time.

Q. State whether true or false.
If a body starts from rest and moves with uniform acceleration, then the displacement of the body is directly proportional to the time of the journey.

If in case of a motion, displacement is directly proportional to the square of time elapsed, what do you think about its (A) velocity (B) acceleration?

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If the displacement of a body is directly proportional to square of time, the object moves with a) uniform velocity b) uniform acceleration c) increasing acceleration d) decreasing acceleration Please tell the correct option and explain

Displacement is proportional to square of time s is displacement and t is time then, s∝t^2 s=kt^2 velocity(v) =ds/dt =2kt acceleration = dv/dt =2k= constant So, the motion of body is constant acceleration. option b is right

If the displacement of a body is directly proportional to square of time, the object moves with
a) uniform velocity
b) uniform acceleration
c) increasing acceleration
d) decreasing acceleration
Please tell the correct option and explain

Displacement is proportional to square of time

s is displacement and t is time then,

s∝t^2

s=kt^2
velocity(v) =ds/dt =2kt

acceleration = dv/dt =2k= constant

So, the motion of body is constant acceleration.

option b is right