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Standard IX

Physics

Simple Pendulum

If the displa...

Question

If the displacement of a particle executing SHM is given by $y = 0.30 sin (220 t + 0.64)$ in metre, then the frequency and maximum velocity of the particle are

35 H z, 66 m / s

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45 H z, 66 m / s

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58 H z, 113 m / s

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35 H z, 132 m / s

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Solution

The correct option is A $35 H z, 66 m / s$
Frequency $(f) = \frac{ω}{2 π}$
$f = \frac{220}{2 \times 22} \times 7 = 35 H z$
and $v_{m a x} = A ω = 0.30 \times 220 = 66 m / s$

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If the displacement of a particle executing SHM is given by y=0.30sin(220t+0.64) in metre, then the frequency and maximum velocity of the particle are

The correct option is A 35Hz,66m/sFrequency (f)=ω2πf=2202×22×7=35Hzand vmax=Aω=0.30×220=66m/s

If the displacement of a particle executing SHM is given by $y = 0.30 sin (220 t + 0.64)$ in metre, then the frequency and maximum velocity of the particle are

The correct option is A $35 H z, 66 m / s$
Frequency $(f) = \frac{ω}{2 π}$
$f = \frac{220}{2 \times 22} \times 7 = 35 H z$
and $v_{m a x} = A ω = 0.30 \times 220 = 66 m / s$