If the displacement of a particle varies with time as $\sqrt{x} = t + 7$ ,then
(1) velocity of the particle is inversely porportional to t
(2) velocity of the particle is directly porportional to t
(3) velocity of the particle is porportional to $\sqrt{t}$
(4) the particle moves with a constant acceleration

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Solution

$x = (t + 7)^{2}$
$v = \frac{d x}{d t} = 2 (t + 7)$
v is linerly proportion with time.

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If the displacement of a particle varies with time as √x=t+7 ,then (1) velocity of the particle is inversely porportional to t (2) velocity of the particle is directly porportional to t (3) velocity of the particle is porportional to √t(4) the particle moves with a constant acceleration

x=(t+7)2v=dxdt=2(t+7)v is linerly proportion with time.

$x = (t + 7)^{2}$
$v = \frac{d x}{d t} = 2 (t + 7)$
v is linerly proportion with time.