If the displacement of particle at any time t is given by s=ut+12at2 where u is initial velocity (constant) and a is acceleration (constant) then, velocity of particle at any time t will be
A
u+at2
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B
u+at
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C
u+2at
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D
ut22+at36
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Solution
The correct option is Bu+at We know velocity is the first derivative of displacement, v=dsdt=u+12a×2t=u+at