If the distance as well as the current in each of two parallel current carrying wires is doubled, the force per unit length acting between them becomes
A
doubled
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B
remains same
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C
quadrupled
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D
halved
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Solution
The correct option is A doubled Force per unit length (F) between two current carrying wires is F=μoI1I22AπN When both I1, I2 and r are doubled then ⇒F′=μo(2I1)(2I2)2A(2π1)=2F