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Question
If the distance between points (p, –5), (2, 7) is 13 units, then p is _____________
If the distance between points (p, –5), (2, 7) is 13 units, then p is _____________
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Solution
The correct option is A. –3 or 7
Given, the distance between points (p, -5) and (2, 7) is 13 units.
∵ The distance between two points (x1,y1) and (x2,y2) is √(x2−x1)2+(y2−y1)2
⇒(2−p)2+(7+5)2=132
⇒(2−p)2=169−144
⇒(2−p)2=25
⇒2−p=±5
case 1:
2−p=5⇒p=−3
case 2:
2−p=−5⇒p=7
Hence, p can be -3 or 7
The correct option is A. –3 or 7
Given, the distance between points (p, -5) and (2, 7) is 13 units.
∵ The distance between two points (x1,y1) and (x2,y2) is √(x2−x1)2+(y2−y1)2
⇒(2−p)2+(7+5)2=132
⇒(2−p)2=169−144
⇒(2−p)2=25
⇒2−p=±5
case 1:
2−p=5⇒p=−3
case 2:
2−p=−5⇒p=7
Hence, p can be -3 or 7
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