If the distance between points P (x, 2) and Q (3, 6) is 10 units, then x =
3
-3
9
-9
PQ = √(3−x)2+(6−(−2))2=10 (3−x)2+(6+2)2=100 (3−x)2=36 3−x=±6 x = -3 or 9
If the distance between points P (x, 2) and Q (3, –6) is 10 units, then x is