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Question
If the distance between points P (x, 2) and Q (3, –6) is 10 units, then x is
If the distance between points P (x, 2) and Q (3, –6) is 10 units, then x is
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Solution
The correct options are
A 3
C 9
PQ = √(3−x)2+(−6−(−2))2=10
squaring both side we get
(3−x)2+(6+2)2=100
(3−x)2+82=100
3−x)2=100−64
3−x)2=100−64
3−x)2=62
x = 3+6 or 3-6
x = -3 or 9
A
3
C
9
PQ = √(3−x)2+(−6−(−2))2=10
squaring both side we get
(3−x)2+(6+2)2=100
(3−x)2+82=100
3−x)2=100−64
3−x)2=100−64
3−x)2=62
x = 3+6 or 3-6
x = -3 or 9
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