If the distance between the earth and sun were to be doubled from its present value, the number of days in a year would be :
Given,
Radius of rotation become double, a2=2a1
By Kepler’s law, T2αa3
T21a31=T22a32
T22=(a2a1)3×T21
T22 =(21)3×T21
T22 =8×T21
T22 =√8×365 days
T2=1032.37 days
Hence, 1032 days in year.