If the distance between the foci and the distance between the two directricies of a hyperbola are in the ratio 5:4 , then the eccentricity of the hyperbola is :
A
54
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B
√54
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C
52
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D
√52
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Solution
The correct option is D√52 Let the hyperbola be x2a2−y2b2=1 ∣∣
∣
∣∣2ae2×ae∣∣
∣
∣∣=54⇒e2=54⇒e=√52