If the distance between the plates of a parallel plate capacitor of capacity 10 -F is doubled- then new capacity will be -

The correct option is D 5μ F Capacitance of a parallel plate capacitor= C=Aϵ_0d∝1d Thus as the distance between plates doubles, the capacitance halves ...

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Standard XII

Physics

Capacitance of Parallel Plate Capacitor

If the distan...

Question

If the distance between the plates of a parallel plate capacitor of capacity 10 $μ$ F is doubled. then new capacity will be :

5 μ F

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20 μ F

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10 μ F

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15 μ F

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Solution

The correct option is D $5 μ F$
Capacitance of a parallel plate capacitor= $C = \frac{A ϵ_{0}}{d} \propto \frac{1}{d}$
Thus as the distance between plates doubles, the capacitance halves and becomes $5 μ F$ .

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If the distance between the plates of a parallel plate capacitor of capacity 10 μF is doubled. then new capacity will be :

The correct option is D 5μFCapacitance of a parallel plate capacitor=C=Aϵ0d∝1dThus as the distance between plates doubles, the capacitance halves and becomes 5μF.

If the distance between the plates of a parallel plate capacitor of capacity 10 $μ$ F is doubled. then new capacity will be :

The correct option is D $5 μ F$
Capacitance of a parallel plate capacitor= $C = \frac{A ϵ_{0}}{d} \propto \frac{1}{d}$
Thus as the distance between plates doubles, the capacitance halves and becomes $5 μ F$ .