If the distance between the points (4, p) and (1, 0) is 5, then p = ___
±4
±2
±2√2
±4√2
Distance between the points (d) = 5 Using distance formula, we get ⇒√(x2−x1)2+(y2−y1)2=d ⇒√(4−1)2+(p−0)2=5⇒9+p2=25⇒p2=16∴p=±4