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Question

If the distance between the points (5,2) and (1,a) is 5 units, then the value of a can be

A
1
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B
1
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C
5
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D
5
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Solution

The correct option is D 5
5=(15)2+(a(2))2
5=16+(a+2)2
On squaring both sides
25=16+(a+2)2
(a+2)2=9
(a+2)=±3
a=5,1

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