If the distance between the points $(8, 7)$ and $(3, y)$ is 13 what is the value of y?

5

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- 19

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19 o r - 5

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5 o r - 19

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none of these

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Solution

The correct option is B $19 o r - 5$
Distance between $(8, 7)$ and $(3, y)$ is
$13 = \sqrt{(8 - 3)^{2} + (7 - y)^{2}}$
$=> 169 = 5^{2} + (7 - y)^{2}$
$=> 169 - 25 = (7 - y)^{2}$
$=> (7 - y)^{2} = 144$
$=> (7 - y)^{2} = 12^{2}$
$=> 7 - y = \pm 12$
$=> 7 - y = 12$ or $7 - y = - 12$
$=> y = - 5$ or $y = 19$

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Similar questions

x

\frac{2 x + 3 y - 19}{y + 5} = 3

y

(6, 0)

(3, y)

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\frac{x}{3} + 5 y = 13; 2 x + \frac{y}{2} = 19

Solve and find value of y.

$\frac{3 x}{2} - \frac{5 y}{3} = - 2$ ; $\frac{x}{2} + \frac{y}{2} = \frac{13}{6}$

\sqrt{27}

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