If the distance between the points A (4, p) and B(1, 0) is 5 then

(a) p = 4 only (b) p = -4 only (c) p = $\pm$ 4 (d) p = 0

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Solution

Applying distance formula, $\sqrt{(1 - 4)^{2} + (0 - p)^{2}} = 5 \Rightarrow 9 + p^{2} = 25 \Rightarrow p^{2} = 16 ∴ p = \pm 4$

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If the distance between the points A (4, p) and B(1, 0) is 5 then (a) p = 4 only (b) p = -4 only (c) p = ±4 (d) p = 0

Applying distance formula, √(1−4)2+(0−p)2=5⇒9+p2=25⇒p2=16∴p=±4

If the distance between the points A (4, p) and B(1, 0) is 5 then

(a) p = 4 only (b) p = -4 only (c) p = $\pm$ 4 (d) p = 0

Applying distance formula, $\sqrt{(1 - 4)^{2} + (0 - p)^{2}} = 5 \Rightarrow 9 + p^{2} = 25 \Rightarrow p^{2} = 16 ∴ p = \pm 4$