1
Question
If the distance between the points (k,−1) and (3, 2) is 5, then the value of k is
If the distance between the points (k,−1) and (3, 2) is 5, then the value of k is
Open in App
Solution
The correct option is B −1
Let the points be A=(x1,y1)=(k,−1)&B=(x2,y2)=(3,2) and distance =d=5Thend=√(x2−x1)2+(y2−y1)2=√(3−k)2+(2+1)2=5⟹k2−6k−7=0⟹(k−7)(k+1)=0∴k=7,k=−1
Let the points be A=(x1,y1)=(k,−1)&B=(x2,y2)=(3,2)
and distance =d=5Thend=√(x2−x1)2+(y2−y1)2=√(3−k)2+(2+1)2=5⟹k2−6k−7=0⟹(k−7)(k+1)=0∴k=7,k=−1
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
