If the distance between the points P (x, 2) and Q (3, –6) is 10 units, then x = _____.
-3
9
Distance between the points (x1,y1) and (x2,y2) is given by
√(x2−x1)2 + (y2−y1)2
∴PQ=√(3−x)2+(−6−2)2=10(3−x)2+(8)2=100(3−x)2+64=100(3−x)2=363−x=±6x=−3 or 9