Question

If the distance between two consecutive base pairs is 0.34 nm, then calculate the length of E. coli DNA having $4.6\times {10}^6$ bp.

• A. 2.2 m
• B. 1.2 m
• C. 1.8 m
• D. 1.56 mm

Answer 1

The correct option is D 1.56 mm

Distance between two base pairs = 0.34 nm or $0.34\times {10}^{-9}$ m

Length of DNA $=0.34\times {10}^{-9}\times 4.6\times {10}^6$
$=1.564\times {10}^{-3}$ m
= 1.564 mm