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Gravitational Potential Energy

If the distan...

Question

If the distance between two particles is reduced to half, the gravitational attraction between them will be

A

Halved

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B

Quadrupled

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C

Doubled

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D

Reduced to a quarter

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Solution

The correct option is C Quadrupled
Gravitational force $= \frac{G m_{1} m_{2}}{r^{2}} = F_{1}$
If distance made $0$ half of original value
$F_{2} = \frac{G m_{1} m_{2}}{{(\frac{r}{2})}^{2}}$
$F_{2} = \frac{4 G m_{1} m_{2}}{r^{2}}$
$F_{2} = 4 F_{1}$

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