Question

If the distance is increased after disconnecting the power source , then electric field inside the capacitor is:

• A. $6\times {10}^{3}V/m$
• B. $3\times {10}^{3}V/m$
• C. $12\times {10}^{3}V/m$
• D. $15\times {10}^{3}V/m$

Answer 1

The correct option is D $15\times {10}^{3}V/m$

If the capacitor are disconnected the voltage across them will rise.

The charge on the capacitor is given as

$Q=CV$

The electric field inside the capacitor is

$E=\frac{V}{d}$

$E<\frac{300}{2}$

The electric field should be smaller than $15\times {10}^{3}V/m$