If the distance of( 4,0) from (a,b) is the double the distance of the point (a,b) from the X AXIS, THEN the relation between a & b is
1) ( a _ 2)² = b^2.2) (a+ 2)² = b^2.3) (a _ 4 )^2.= 3b^2.4) none

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Solution

the distance of( 4,0) from (a,b) = √(a-4)² + (b²)
= √(a²-8a+16+b²)

Now distance of the point (a,b) from the X AXIS, means, distance between points (a,b) and (a,0)
Distance = √(( a²-a²) + b² )
= √b²
=b

Now its given that distance of( 4,0) from (a,b) is the double the distance of the point (a,b) from the X AXIS,
So,
√(a²-8a+16+b²) =2b
Squaring both sides and adding,
a²-8a+16+b² = 4b²
a²-8a+16 =3b²
Or,
(a-4)² = 3b²

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