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Question

If the distance of a point (a,a,a) from the origin is 108, then the value of a is

A
9
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B
6
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C
9
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D
6
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Solution

The correct options are
C 6
D 6
Distance between (x1,y1) and (x2,y2) is (x1x2)2+(y1y2)2
Distance between (0,0,0) and (a,a,a) is (a0)2+(a0)2+(a0)2

3×(a)2=108=63a=±6

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