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Question

If the distance of any point (x, y) from origin is defined as d(x,y)=max|x|,|y|, then the locus of the point (x, y) where d (x, y) = 1 is

A
a circle
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B
a square
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C
a triangle
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D
parallelogram but not square.
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Solution

The correct option is B a square
d(x,y)=max|x|,|y|

When |x|>|y|,d(x,y)=|x|=1
x=±1 which represent AB and CD segment.
When |x|<|y|,d(x,y)=|y|=1
y=±1 which represent AD and BC segment.
Locus is a square ABCD.

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