If the distance of any point (x, y) from origin is defined as d(x,y)=max|x|,|y|, then the locus of the point (x, y) where d (x, y) = 1 is
A
a circle
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B
a square
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C
a triangle
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D
parallelogram but not square.
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Solution
The correct option is B a square d(x,y)=max|x|,|y| When |x|>|y|,d(x,y)=|x|=1 ⇒x=±1 which represent AB and CD segment. When |x|<|y|,d(x,y)=|y|=1 ⇒y=±1 which represent AD and BC segment. ∴ Locus is a square ABCD.