If the distance of any point (x,y) from the origin is defined as d(x,y)=max{|x|,|y|} then the locus of the point (x,y) where d(x,y)=1, is
A
A square
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B
A circle
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C
A triangle
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D
None the above
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Solution
The correct option is A A square We have d(x,y)=1 ⇒max{|x|,|y|}=1 ⇒|x|≤1 |y|≤1 ⇒−1≤x≤1 and −1≤y≤1 ∴ Locus of (x,y) is the squaring having its vertices at (1,1),(−1,1),(−1,−1) and (1,−1)