If the distance of Earth from the Sun were half the present value, how many days will make one year?

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Solution

By using Kepler’s law

$T^{2} \propto r^{3}$

By substituting the time period and the value of radius we get

${(\frac{T_{1}}{T_{2}})}^{2} = {(\frac{r_{1}}{r_{2}})}^{3}$

${(\frac{365}{T_{2}})}^{2} = {(\frac{2 r_{1}}{r_{1}})}^{3}$

$T_{2} = \frac{365}{2 \sqrt{2}}$

The time period will be $129 d a y s$

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Similar questions

If the distance between the earth and the sun were reduces to half its present value, Then the number of days in one year would have been

T^{2} \propto R^{3}

If the distance between the Earth and the Sun were half its present value, the approximate number of days in a year on the Earth would have been:

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