If the distance of two lines passing through origin from the point (x1,y1) is 'd',then the equation of lines is
If the equation of line is y = mx and the length of perpendicular drawn on it from the point (x1,y1) is d, then y1−mx1√1+m2=±d⇒(y1−mx1)2=d2(1+m2). But m=yx, therefore on eliminating 'm', the required equation is (xy1−yx1)2=d2(x2+y2).