Question

If the distance $s$ travelled by a particle in time $t$ is given by $s=t^2-2t+5$, then its acceleration is

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

The correct option is C 2

Given distance $\left(s\right)=t^2-2t+5$

$\therefore$ velocity $\left(v\right)$ $=\frac{dx}{dt}$ $=2t-2$

Acceleration $\left(a\right)$ $=\frac{dv}{dt}=2$

$\therefore acceleration=2$