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Multiplication with Vectors

If the dot pr...

Question

If the dot product of the two vectors is $2 \sqrt{3}$ unit and the magnitude of cross product is $2$ units. The angle between the two vectors is:

A

π / 6

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B

π / 4

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C

π / 3

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D

π / 2

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Solution

The correct option is A $π / 6$
Given $\to A \cdot \to B = A B cos θ = 2 \sqrt{3} a n d \to A \times \to B = A B sin θ = 2$
$tan θ = \frac{2}{2 \sqrt{3}} = \frac{1}{\sqrt{3}} o r θ = \frac{π}{6}$

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