Question

If the earth stops rotating about its axis what will be the change in the value of 'g' at a place on the equator ? Assume radius of the Earth $R=6.2\times {10}^{6}m$

Answer 1

Variation of $g$ due to rotation is given by$:$

$g=g^1-w^{2}R$

If earth stops rotating

$w=0$

$g=g^{\prime }-0$

$\Rightarrow g=g^{\prime }$

The value of $g$ increases

$g=\frac{GM}{R^2}$

$g_{earth}=\frac{6.67\times {10}^{-11}\times 5.97\times {10}^{24}kg}{{\left(6400000\right)}^2}$ $=9.8m/s^2$

WE get, $g_{earth}=9.8m/s^2$