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Question

If the eccentricity of a hyperbola is 54, then find the eccentricity of its conjugate.

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Solution

Fact: Sum of square of reciprocal of eccentricities of hyperbola and its conjugate is 1

Let eccentricity of the conjugate is e, then
1e2+1625=1
1e2=11625=925
e2=259
e=53

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