If the eccentricity of a hyperbola is √2 and if the distance between the foci is 16, then its equation is
x2−y2=32
Given that distance between foci, 2c =16
c=8; e=√2
a=ce=8√2=4√2b=√c2−a2=√32=4√2
The equation of the hyperbola is
x232−y232=1⇒x2−y2=32