Question

If the eccentricity of an ellipse be $\frac{1}{\sqrt{2}}$ , then its latus rectum is equal to its

• A. Minor axis
• B. Semi-minor axis
• C. Major axis
• D. Semi-major axis

Answer 1

The correct option is D

Semi-major axis

e = $\frac{1}{\sqrt{2}}$ ; Latus rectum = $\frac{2b^2}{a}=\frac{2a^2}{a}(1-\frac{1}{2})=a$