CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If the eccentricity of the hyperbola  x2y2sec2α=5is3  times the eccentricity of the ellipse x2sec2α+y2=25, then the value of α is



A

π6

loader
B

π4

loader
C

π3

loader
D

π2

loader

Solution

The correct option is C

π4


x25y25cos2α=1e21=1+cos2α       (1)
and x225cos2α+y225=1e22=sin2α      (2)
Given that e1=3e2
e21=3e22
Putting values from equation (1) and (2) 
1+cos2α=3sin2αsinα=12α=π4


Co-Curriculars

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image