Question

If the edge length of a body-centred unit cell is $$400$$ pm, what will be the approximate radius of the atom present in it? (in pm)

A
200
B
141
C
173
D
924

Solution

The correct option is C $$173$$For body-centred unit cell, the radius (r) and the edge length (a) are related by the expression$$4r=\sqrt 3 a$$ $$\displaystyle r=0.433 \times a$$ $$\displaystyle r=0.433 \times 400$$ pm $$\displaystyle r = 173$$ pm.Hence, the correct option is $$\text{C}$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More