Question

If the edge length of a body-centred unit cell is $400$ pm, what will be the approximate radius of the atom present in it? (in pm)

• A. $200$
• B. $141$
• C. $173$
• D. $924$

Answer 1

The correct option is C $173$

For body-centred unit cell, the radius (r) and the edge length (a) are related by the expression

$4r=\sqrt{3}a$

$r=0.433\times a$

$r=0.433\times 400$ pm

$r=173$ pm.

Hence, the correct option is $\text{C}$