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Question

If the edge length of a body-centred unit cell is $$400$$ pm, what will be the approximate radius of the atom present in it? (in pm)


A
200
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B
141
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C
173
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D
924
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Solution

The correct option is C $$173$$
For body-centred unit cell, the radius (r) and the edge length (a) are related by the expression

$$4r=\sqrt 3 a$$

 $$\displaystyle r=0.433 \times a$$

 $$\displaystyle r=0.433 \times 400 $$ pm 

$$\displaystyle r = 173$$ pm.

Hence, the correct option is $$\text{C}$$

Chemistry

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