If the efficiency of a machine is $60 %$ and it does $90 J$ of work, what is the input work?

$200 J$

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$100 J$

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$350 J$

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$150 J$

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Solution

The correct option is D
$150 J$

Efficiency $(n) = 60 %$
Output work = $90 J$

$n = \frac{O u t p u t W o r k}{I n p u t W o r k}$

$\Rightarrow I n p u t W o r k = \frac{O u t p u t W o r k}{n}$

$\Rightarrow I n p u t W o r k = \frac{90 J \times 100}{60} = 150 J$

$∴$ The input work done on the machine is $150 J$ .

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