If the electric field intensity is given by E-x-x-y-y-z-z Volt-m the potential difference between X2- 0- 0 and Y1- 2- 3 is

Ans :(c) V= ∫E.dl = [ ∫_1^2xdx+∫_2^0ydy+∫_3^0zdz] EQUATION = 12[2^2 1^2+0^2 2^2+0^2 3^2] = 12× 10=5 V ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Classification of Vector Fields and Important Vector Identities

If the electr...

Question

If the electric field intensity is given by
$\to E = (x {^u}_{x} + y {^u}_{y} + z {^u}_{z})$ Volt/m the potential difference between X(2, 0, 0) and Y(1, 2, 3) is

+1 volt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1 volt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+5 volt

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+6 volt

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C +5 volt
Ans :(c)

$V = - \int \to E . \to d l$

$= - [2 \int 1 x d x + 0 \int 2 y d y + 0 \int 3 z d z]$

EQUATION

$= - \frac{1}{2} [2^{2} - 1^{2} + 0^{2} - 2^{2} + 0^{2} - 3^{2}]$

$= - \frac{1}{2} \times - 10 = 5 V$

Suggest Corrections

Similar questions

The variation of electric field intensity E versus distance x is shown in the figure. The potential difference between the point x = 0 to x = 3 m is

Q. An electric field (in

V / m

) is given by

E = 10 x^{3}

. Determine the potential difference, in volts, between

x = 0 m

and

x = 3 m

Q. The potential of the electric field produced at a point

(x, y, z)

is given at

V = x^{2} + 4 x + 5

where

x, y, z

are in meters and

V

is in volts. What is the intensity of the electric field at

(2, 1, 0)

The potential difference between the two plates of a parallel plate condenser is $250 v o l t$ and the distance between them is $5 c m$ . The uniform electric field intensity is:

Q. Define intensity of electric field (E) and the potential differences (V) between two points. Derive the relation between them.

Join BYJU'S Learning Program

If the electric field intensity is given by →E=(x^ux+y^uy+z^uz) Volt/m the potential difference between X(2, 0, 0) and Y(1, 2, 3) is

The correct option is C +5 voltAns :(c) V=−∫→E.→dl =−[2∫1xdx+0∫2ydy+0∫3zdz] EQUATION =−12[22−12+02−22+02−32] =−12×−10=5V

If the electric field intensity is given by
$\to E = (x {^u}_{x} + y {^u}_{y} + z {^u}_{z})$ Volt/m the potential difference between X(2, 0, 0) and Y(1, 2, 3) is

The correct option is C +5 volt
Ans :(c)

$V = - \int \to E . \to d l$

$= - [2 \int 1 x d x + 0 \int 2 y d y + 0 \int 3 z d z]$

EQUATION

$= - \frac{1}{2} [2^{2} - 1^{2} + 0^{2} - 2^{2} + 0^{2} - 3^{2}]$

$= - \frac{1}{2} \times - 10 = 5 V$