If the electric flux entering and leaving and enclosed surface respectively is -1 and -2- the electric charge inside the surface will be

The correct option is A (ϕ_2 ϕ_1)ϵ_0 Net electric flux: ϕ_2 ϕ_1 ϕ_N = Q_encε_0 Q_enc = ε_0(ϕ_2 ϕ_1) ...

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Byju's Answer

Standard XII

Physics

Gauss's Law

If the electr...

Question

If the electric flux entering and leaving and enclosed surface respectively is $ϕ_{1}$ and $ϕ_{2}$ , the electric charge inside the surface will be

(ϕ_{2} - ϕ_{1}) ϵ_{0}

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(ϕ_{2} + ϕ_{1}) / ϵ_{0}

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(ϕ_{2} - ϕ_{1}) / ϵ_{0}

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(ϕ_{2} + ϕ_{1}) ϵ_{0}

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Solution

The correct option is A $(ϕ_{2} - ϕ_{1}) ϵ_{0}$
Net electric flux: $ϕ_{2} - ϕ_{1}$
$ϕ_{N} = \frac{Q_{e n c}}{ε_{0}}$
$Q_{e n c} = ε_{0} (ϕ_{2} - ϕ_{1})$

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If the electric flux entering and leaving and enclosed surface respectively is ϕ1 and ϕ2, the electric charge inside the surface will be

The correct option is A (ϕ2−ϕ1)ϵ0Net electric flux: ϕ2−ϕ1ϕN=Qencε0Qenc=ε0(ϕ2−ϕ1)

If the electric flux entering and leaving and enclosed surface respectively is $ϕ_{1}$ and $ϕ_{2}$ , the electric charge inside the surface will be

The correct option is A $(ϕ_{2} - ϕ_{1}) ϵ_{0}$
Net electric flux: $ϕ_{2} - ϕ_{1}$
$ϕ_{N} = \frac{Q_{e n c}}{ε_{0}}$
$Q_{e n c} = ε_{0} (ϕ_{2} - ϕ_{1})$