If the electron has a speed of 600 m/sec with an accuracy of 0.005%. The certainty with which the position of the electron can be located in:

1.96 \times 10^{- 3}

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1.058 \times 10^{- 3}

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2.69 \times 10^{- 2}

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3.58 \times 10^{- 2}

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Solution

The correct option is A $1.96 \times 10^{- 3}$
Again, use
$Δ x = h / 4 π m Δ v$ .
A/q $Δ v = 0.005 / 100 \times 600 m / s = 5 \times 10^{- 5} \times 600 m / s = 0.03 m / s$ .

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If the electron has a speed of 600 m/sec with an accuracy of 0.005%. The certainty with which the position of the electron can be located in:

The correct option is A 1.96×10−3Again, use Δx=h/4πmΔv.A/q Δv=0.005/100×600m/s=5×10−5×600m/s=0.03m/s.

The correct option is A $1.96 \times 10^{- 3}$
Again, use
$Δ x = h / 4 π m Δ v$ .
A/q $Δ v = 0.005 / 100 \times 600 m / s = 5 \times 10^{- 5} \times 600 m / s = 0.03 m / s$ .